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/ \[ = 0 \]
\[ = 0 \]
February 22, 2026
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\[ 3(x - 3)(x - 1) = 0 \]
\[ f(2) = 2(2)^3 - 9(2)^2 + 12(2) - 4 \]
\[ = 16 - 36 + 24 - 4 \]
#### \(f(2) = 0\)
\[ g'(1) = 20(1)^3 - 9(1)^2 + 2 \]
\[ = 20 - 9 + 2 = 13 \]
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