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/ \[ (3k)(2k) = 6k^2 = c \]
\[ (3k)(2k) = 6k^2 = c \]
February 22, 2026
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\[ x^2 + bx + c = 0 \]
\[ 3k + 2k = 5k = -b \]
\[ b = -5k \]
\[ c = 6\left(-\frac{b}{5}\right)^2 = 6 \cdot \frac{b^2}{25} = \frac{6b^2}{25} \]
\[ b = -5k, \quad c = 6k^2 \]
\[ G(t) = \frac{3t^2 + 2t + 1}{t + 1} \]
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