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/ \( a = 0 \) or \( 2 \) → 2 choices
\( a = 0 \) or \( 2 \) → 2 choices
February 22, 2026
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\( b \in \{0, 2\} \) (since \( b \leq 2 \), even)
\( c \in \{0\} \) (since \( c \leq 1 \), and only even choice is 0)
So possible combinations:
\( b = 0 \) or \( 2 \) → 2 choices
\( c = 0 \) → 1 choice
Total: \( 2 \times 2 \times 1 = 4 \) perfect square divisors.
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