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Question: What is the sum of all odd divisors of the patent classification number 225?
The sum of divisors is $(1 + 3 + 9)(1 + 5 + 25) = 13 imes 31 = 403$.
Question: What is the remainder when the sum of the first 10 odd numbers is divided by 11?
Solution: The first 10 odd numbers are $1, 3, 5, 7, 9, 11, 13, 15, 17, 19$. Their sum is:
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