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Substitute \( x = 1 \) into \( f(x) \):
\( f(1) = 2(1)^2 - 4(1) + 1 = 2 - 4 + 1 = -1 \).
The vertex is at \( (1, -1) \).
#### \( (1, -1) \)
Evaluate the limit \( \lim_{x o 3} rac{x^2 - 9}{x - 3} \).
Factor the numerator: \( x^2 - 9 = (x - 3)(x + 3) \).
Simplify the expression: \( rac{(x - 3)(x + 3)}{x - 3} = x + 3 \) for \( x
eq 3 \).
Evaluate the limit: \( \lim_{x o 3} (x + 3) = 3 + 3 = 6 \).
The limit is 6.