\omega^4 + 3\omega^3 - 2\omega^2 + \omega + 5 = a\omega + b
Related Articles
- x^4 + 3x^3 - 2x^2 + x + 5 = (x^2 - x + 1)Q(x) + ax + b
- Let \(\omega\) be a root of \(x^2 - x + 1 = 0\). Then \(\omega^2 = \omega - 1\), and \(\omega^3 = \omega(\omega - 1) = \omega^2 - \omega = (\omega - 1) - \omega = -1\). So \(\omega^3 = -1\), and \(\omega^6 = 1\).
- Now evaluate at \(x = \omega\):
- We compute each term:
- \(\omega^4 = \omega \cdot \omega^3 = \omega(-1) = -\omega\)
- \(3\omega^3 = 3(-1) = -3\)
Trending Articles
DID THIS MARVEL DISNEY+ SETUP EXPOSE SECRETS NO ONE WAS SUPPOSED TO SEE?
Secrets Revealed: Marvel Rivals Exposed in Stunning Nude Shots
Shocking Nude Clips Fuel Hottest Rivalry Between Marvel Legends
Hidden Synergy: Marvel Rivals Locked in Daring Nude Scenes That Shock Fans
They Didn’t Just Compete—Marvel Rivals Were Stripped in Unbelievable Nudes
The True Battle Behind the Scenes: Marvel Heroes Slip in Bare Nude Moments
Marvel Rivals Reloaded – The Hidden Rivals Mode Teens Won’t Believe What Unleashed
You Don’t Believe What These Marvel Rivals Rivals Did – Mind-Blowing Mods Exposed
Marvel Rivals Shocks: The Secret Rivals Team No One Saw Coming!
From Zero to Hero – Marvel Rivals Mods Rival Reality Itself