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Substitute \( x = 1 \) into \( f(x) \):\( f(1) = 2(1)^2 - 4(1) + 1 = 2 - 4 + 1 = -1 \).The vertex is at \( (1, -1) \).#### \( (1, -1) \)Evaluate the limit \( \lim_{x o 3} rac{x^2 - 9}{x - 3} \).Factor the numerator: \( x^2 - 9 = (x - 3)(x + 3) \).Simplify the expression: \( rac{(x - 3)(x + 3)}{x - 3} = x + 3 \) for \( xeq 3 \).Evaluate the limit: \( \lim_{x o 3} (x + 3) = 3 + 3 = 6 \).The limit is 6.