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/ \( \sum_{c=0}^{1} 5^c = 1 + 5 = 6 \)
\( \sum_{c=0}^{1} 5^c = 1 + 5 = 6 \)
February 22, 2026
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= \left( \sum_{a=1}^{2} 2^a \right) \cdot \left( \sum_{b=0}^{1} 3^b \right) \cdot \left( \sum_{c=0}^{1} 5^c \right)
\( \sum_{a=1}^{2} 2^a = 2 + 4 = 6 \)
\( \sum_{b=0}^{1} 3^b = 1 + 3 = 4 \)
Multiply:
\cdot 4 \cdot 6 = 144
Alternatively, recall the formula for sum of divisors with \( a \geq 1 \):
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