$ x + 3 \equiv 0 \pmod{7} $, $ \pmod{8} $ → $ x \equiv -3 \pmod{7} $, $ \pmod{8} $
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- Suppose the intended question was:
- Find a two-digit positive integer that is three less than a multiple of 7 and three less than a multiple of 8.
- Then $ x \equiv -3 \pmod{7} $, $ x \equiv -3 \pmod{8} $ → $ x \equiv 4 \pmod{7} $, $ x \equiv 5 \pmod{8} $? No.
- So $ x \
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